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This would more appropriately have been placed in the Calculus and Beyond homework help section, even if it isn't homework it is of that nature and level Is there someone who can explain why this is true, or point me to an online resource that provides a proof of it?DEPARTMENT OF ELECTRICAL AND COMPUTER ENGINEERING, THE UNIVERSITY OF NEW MEXICO EC14 Signals and Systems Summer 13 Instructor Daniel Llamocca

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In probability theory, the expected value of a random variable, denoted ⁡ or ⁡ , is a generalization of the weighted average, and is intuitively the arithmetic mean of a large number of independent realizations of The expected value is also known as the expectation, mathematical expectation, mean, average, or first momentExpected value is a key concept in economics, finance, and manyHere X is a rv having the same distribution as Xj The sum S =åN j=1 Xj where the number in the sum, N is also a random variable and is independent of the Xj's The following statement now follows from Theorem 1 Theorem 2 (i) ES=E(X)£E(N)=aE(N) (ii) Var(S)=Var(X)£E(N)E(X)2 £Var(N)=s2E(N)a2Var(N) I don't think that there's any way ln(esupx/sup1) can be simplified Near x=0, I suppose you could expand esupx/sup, in terms of a series expansion, and then discard higher order terms, and then expand the resulting log, again in terms of a power series

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Start like this * We know math(x1)\mid (x1)/math So math(x1)\equiv 0\mod (x1)\tag*{}/math * Add math1/math to both sides mathx\equiv 1\mod (x1)\tagStart your free trial In partnership with The value of e^ln (x) is x This is because ln (x) is the inverse function of e (x), which means that applying the function f (x) = e^x reverses the effect of the function f (x) = ln (x) The definition of the natural logarithm ln (x) is that it is the area under the curve y = 1/t between t = 1 and t = x As a result, the value of ln (e) is 1

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I assume you are looking for math\sum_{n\geqslant 1}\frac{x^n}n/math We restrict the value of mathx/math to open regions in math\mathbb R/math or math\mathbb C/math where the series converges One clever way to compute that is bySolve for x natural log of e^x=5 ln (ex) = 5 ln ( e x) = 5 The exponent of a factor inside a logarithm can be expanded to the front of the expression using the third law of logarithms The third law of logarithms states that the logarithm of a power of x x is equal to the exponent of that power times the logarithm of x x (logb(xn) = nlogb (x

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